Section 2.1 Quadratic Functions
-This chapter is about quadratic functions
Polynomial Function is f(x)= ax^n+bx^(n-1)+cx^(n-2)...+z
Quadratic Fn: f(x)=ax²+bx+c
Standard Form of a parabola: f(x)=a(x-h)²+k
Vertex: (h,k)
Axis of Symmetry: x=h
x-int: set the equation to 0 and solve
Example 1) Find the vertex, Axis of Symmetry, and x-intercepts of f(x) = 2x²+8x+7
f(x) = 2(x²+4x)+7 *factor out "a" from only the 1st two terms
= 2(x²+4x+4)+7-8 *find half of the underlined term and double it to find the
bold term; add or subtract the product of the italicized numbers
to the end of the problem
= 2(x+2)² - 1
vertex: (-2,-1) *the opposite sign of the bold number is your x and the underlined number is your y
AoS: x=-2 *the x in your vertex is the AoS
2(x+2)²-1=0 *set equal to 0 to find x-int
= *square both sides to get rid of the exponent
x+2=+
X=-2+ *subtract 2 from both sides to find x-int
How to find the standard form of a palabora:
Ex: Vertex (3,2) and it goes through a point (1,-6)
Reminder: Standard Form: f(x)=a(x-h)²+k
-6=a(1-3)²+2 *add in all the terms given to you in the problem
-6=a(2)+2
-8=2a *subtract 2 from both sides
-4=a *divide both sides by 4 to find a
Final answer: f(x)=-4(x-3)²+2
To find maximum or minimum for vertex: x= -b/2a
Comments (1)
Anonymous said
at 8:23 pm on Jan 8, 2008
Can you find the word "palabra"?
Also, it's hard not to get bogged down in your example problems... changing the spacing/formatting would be nice. 18/20
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